Jump to content
SAU Community

Recommended Posts

The tank had to be a personal vehicle. No way would they send a tank up from Victoria for a formal unless they were going to be able to recruit people. (like a recruiting stand) :P

Was it an actually tank or a smaller armoured vehicle?

(sorry, i like my armoured vehicles :()

62 tons combat layden and it would have been a publicity thing then. They are allowed on roads because they actually have a lesser ground pressure than the old Leopard tanks we had due to a wider track, but are still limited to where they can go. Infact to be qualified to drive one in the army you have to have a certain amount of time driving on a main road.

WHATS A CROCK OF S^%&!!!!

After forking out nearly $800 today for the 'privelidge' of being able to drive a road registered and third party insured car for another year today, I have zero sense of humour about this sort of revenue rasing! A lot of money to thin air! They seem to just try and take the fun out of every aspect of motoring through smacking taxes, levies, charges or fees onto absolutely everything they can think of!

But I'll tell you this as stated on the previous page they may be able to defect you but in no way would it be enforcable to fine someone for simply dropping a friend (or ralative) off. You could even go so far as to hand the driver of the car cash right in front of an RTA inspector or Police officer and simply state; "thanks for the lift. let me pay for some fuel". Thats not payment for services, but a reimbursment. If they fine you - they are wrong! Argue it! Don't take this crap lying down people. I remember when I had my year 12 formal and the likes of WHYTRY, SINISTA, CHOOCHOOBA, NATH32, (I know I'm forgetting a few people here and I'm really sorry LOL) rocked up and let me tell you... we had one hell of an entrance! I was so grateful to all those guys for the lift and I don't want to see this great past time go out the window.

Fair enough if your car is defectable! They can get you on that but as you are not A. a registered transport business or B. receiving money from the patron (liftee) for services offered (;-)... if you want to charge), they have nothing.

OK im guessing datto260z is in the army

22082005.jpg

I drove and gunned these until December last year, so I was in the army. It was over rated most of the time though (Sorry Shawn).

In the hanger next door was about 12 Abrams, one of which was the one at the Nats and the formal.

I drove and gunned these until December last year, so I was in the army. It was over rated most of the time though (Sorry Shawn).

In the hanger next door was about 12 Abrams, one of which was the one at the Nats and the formal.

Cool , a mate i went to school with is going to afghanistan soon( Howard hasn`t told the public about it yet)

Its an M113 scorpion varient I think, looks a bit different in red though :P My old unit had them before they went to ASLAVs when they were in Sydney.

They have been used a few times on rampages, one in WA, another in Sydney years ago and one recently, I think ex Nam vets are usually the culprits, but I could be wrong. Poor fellas.

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now


  • Similar Content

  • Latest Posts

    • Yeah, that's fine**. But the numbers you came up with are just wrong. Try it for yourself. Put in any voltage from the possible range and see what result you get. You get nonsense. ** When I say "fine", I mean, it's still shit. The very simple linear formula (slope & intercept) is shit for a sensor with a non-linear response. This is the curve, from your data above. Look at the CURVE! It's only really linear between about 30 and 90 °C. And if you used only that range to define a curve, it would be great. But you would go more and more wrong as you went to higher temps. And that is why the slope & intercept found when you use 50 and 150 as the end points is so bad halfway between those points. The real curve is a long way below the linear curve which just zips straight between the end points, like this one. You could probably use the same slope and a lower intercept, to move that straight line down, and spread the error out. But you would 5-10°C off in a lot of places. You'd need to say what temperature range you really wanted to be most right - say, 100 to 130, and plop the line closest to teh real curve in that region, which would make it quite wrong down at the lower temperatures. Let me just say that HPTuners are not being realistic in only allowing for a simple linear curve. 
    • I feel I should re-iterate. The above picture is the only option available in the software and the blurb from HP Tuners I quoted earlier is the only way to add data to it and that's the description they offer as to how to figure it out. The only fields available is the blank box after (Input/ ) and the box right before = Output. Those are the only numbers that can be entered.
    • No, your formula is arse backwards. Mine is totally different to yours, and is the one I said was bang on at 50 and 150. I'll put your data into Excel (actually it already is, chart it and fit a linear fit to it, aiming to make it evenly wrong across the whole span. But not now. Other things to do first.
    • God damnit. The only option I actually have in the software is the one that is screenshotted. I am glad that I at least got it right... for those two points. Would it actually change anything if I chose/used 80C and 120C as the two points instead? My brain wants to imagine the formula put into HPtuners would be the same equation, otherwise none of this makes sense to me, unless: 1) The formula you put into VCM Scanner/HPTuners is always linear 2) The two points/input pairs are only arbitrary to choose (as the documentation implies) IF the actual scaling of the sensor is linear. then 3) If the scaling is not linear, the two points you choose matter a great deal, because the formula will draw a line between those two points only.
    • Nah, that is hella wrong. If I do a simple linear between 150°C (0.407v) and 50°C (2.98v) I get the formula Temperature = -38.8651*voltage + 165.8181 It is perfectly correct at 50 and 150, but it is as much as 20° out in the region of 110°C, because the actual data is significantly non-linear there. It is no more than 4° out down at the lowest temperatures, but is is seriously shit almost everywhere. I cannot believe that the instruction is to do a 2 point linear fit. I would say the method I used previously would have to be better.
×
×
  • Create New...