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even if you have to fly, its cheaper than losing 2k.

i feel really sorry for people this happens to, but why would you give someone you dont know, with no history on here, no trader rating etc 2k.

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I'm heading to Kingaroy this coming weekend, if you have a address i will be MORE then happy to pay a visit and collect anything there to the value of what he owes you, plus a little something for my time.

Have quite a bit of family up there so have no problems rocking up there...

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Already got his address his changed his mob # too the flamin mongrel

man hope it all works out, i got f**king ripped off once too buying a msd ignition unit for $500... i couldnt imagine loosing 2g i would go mental...

if it helps you can clearly see the plates of what looks to be his car in his personal photo - 838 HGO

just steal the car, part it out and call it even haha...

if you are reading this charlie you wanker you are going to get owned one day and hopefully that day is pretty soon you juvenile delinquent wanker... how hard do you think its going to be to track you down in the oh so big town of kingaroy anyways.... bet there arent that many skylines out there ay hahahahaha

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You said it mate. How can he honestly think his gonna get away with it. R31Love is gonna pay him a visit with a few mates and aint gonna leave empty handed!

nice bro, hope you come out on top man... r31love - you are a champ :down:

lukas 33 - id pm ya back but my post count is 2 lol.... i got ripped off on eBay by a guy named 0xb073

let us all know how it pans out anyways man... love hearing personal justice stories

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    • Yeah, that's fine**. But the numbers you came up with are just wrong. Try it for yourself. Put in any voltage from the possible range and see what result you get. You get nonsense. ** When I say "fine", I mean, it's still shit. The very simple linear formula (slope & intercept) is shit for a sensor with a non-linear response. This is the curve, from your data above. Look at the CURVE! It's only really linear between about 30 and 90 °C. And if you used only that range to define a curve, it would be great. But you would go more and more wrong as you went to higher temps. And that is why the slope & intercept found when you use 50 and 150 as the end points is so bad halfway between those points. The real curve is a long way below the linear curve which just zips straight between the end points, like this one. You could probably use the same slope and a lower intercept, to move that straight line down, and spread the error out. But you would 5-10°C off in a lot of places. You'd need to say what temperature range you really wanted to be most right - say, 100 to 130, and plop the line closest to teh real curve in that region, which would make it quite wrong down at the lower temperatures. Let me just say that HPTuners are not being realistic in only allowing for a simple linear curve. 
    • I feel I should re-iterate. The above picture is the only option available in the software and the blurb from HP Tuners I quoted earlier is the only way to add data to it and that's the description they offer as to how to figure it out. The only fields available is the blank box after (Input/ ) and the box right before = Output. Those are the only numbers that can be entered.
    • No, your formula is arse backwards. Mine is totally different to yours, and is the one I said was bang on at 50 and 150. I'll put your data into Excel (actually it already is, chart it and fit a linear fit to it, aiming to make it evenly wrong across the whole span. But not now. Other things to do first.
    • God damnit. The only option I actually have in the software is the one that is screenshotted. I am glad that I at least got it right... for those two points. Would it actually change anything if I chose/used 80C and 120C as the two points instead? My brain wants to imagine the formula put into HPtuners would be the same equation, otherwise none of this makes sense to me, unless: 1) The formula you put into VCM Scanner/HPTuners is always linear 2) The two points/input pairs are only arbitrary to choose (as the documentation implies) IF the actual scaling of the sensor is linear. then 3) If the scaling is not linear, the two points you choose matter a great deal, because the formula will draw a line between those two points only.
    • Nah, that is hella wrong. If I do a simple linear between 150°C (0.407v) and 50°C (2.98v) I get the formula Temperature = -38.8651*voltage + 165.8181 It is perfectly correct at 50 and 150, but it is as much as 20° out in the region of 110°C, because the actual data is significantly non-linear there. It is no more than 4° out down at the lowest temperatures, but is is seriously shit almost everywhere. I cannot believe that the instruction is to do a 2 point linear fit. I would say the method I used previously would have to be better.
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