Jump to content
SAU Community

Recommended Posts

im not sure, kinda hard to understand what the old bat babbles on, she said it makes a really bad noise, and runs like shit, not in those words of course.

but as i said, the body/interior looks good condish, good for the $ she wants for sure.

well im off to bed to, im with steve, i need all the beauty sleep i can get! lol

how about a KE70? anyone got one for sale or know someone selling one?

think its time for my car to become a weekend-er

i think there is one in adel for sale! in the general for sale cars thread!!

Sean/Boostworx runs in the improved production with a little 808 I believe it is.

In his old rx7 I believe his best time around mallala was a low 1min 17?

Yeh thats right, He's building his 808 now, Our lap record holder has a 808 also and is a team mate, runs a BP18T 1.8ltr ran a 1:15, our cars are also restricted, has a 36mm restrictor smack bang in front of the turbo, only running about 200kw!!

Q: What should one pay for an SAFC II Tune? picking one up for the legnum, will install it myself and then look to have it tuned. Was thinking of going to see Shaun (boostworx) but as he doesnt have AWD dyno would mean he would have to hire out someone elses and may affect cost.

Either way, I would guess no more than $200 - is this fair?

Guest
This topic is now closed to further replies.



  • Similar Content

  • Latest Posts

    • Yeah, that's fine**. But the numbers you came up with are just wrong. Try it for yourself. Put in any voltage from the possible range and see what result you get. You get nonsense. ** When I say "fine", I mean, it's still shit. The very simple linear formula (slope & intercept) is shit for a sensor with a non-linear response. This is the curve, from your data above. Look at the CURVE! It's only really linear between about 30 and 90 °C. And if you used only that range to define a curve, it would be great. But you would go more and more wrong as you went to higher temps. And that is why the slope & intercept found when you use 50 and 150 as the end points is so bad halfway between those points. The real curve is a long way below the linear curve which just zips straight between the end points, like this one. You could probably use the same slope and a lower intercept, to move that straight line down, and spread the error out. But you would 5-10°C off in a lot of places. You'd need to say what temperature range you really wanted to be most right - say, 100 to 130, and plop the line closest to teh real curve in that region, which would make it quite wrong down at the lower temperatures. Let me just say that HPTuners are not being realistic in only allowing for a simple linear curve. 
    • I feel I should re-iterate. The above picture is the only option available in the software and the blurb from HP Tuners I quoted earlier is the only way to add data to it and that's the description they offer as to how to figure it out. The only fields available is the blank box after (Input/ ) and the box right before = Output. Those are the only numbers that can be entered.
    • No, your formula is arse backwards. Mine is totally different to yours, and is the one I said was bang on at 50 and 150. I'll put your data into Excel (actually it already is, chart it and fit a linear fit to it, aiming to make it evenly wrong across the whole span. But not now. Other things to do first.
    • God damnit. The only option I actually have in the software is the one that is screenshotted. I am glad that I at least got it right... for those two points. Would it actually change anything if I chose/used 80C and 120C as the two points instead? My brain wants to imagine the formula put into HPtuners would be the same equation, otherwise none of this makes sense to me, unless: 1) The formula you put into VCM Scanner/HPTuners is always linear 2) The two points/input pairs are only arbitrary to choose (as the documentation implies) IF the actual scaling of the sensor is linear. then 3) If the scaling is not linear, the two points you choose matter a great deal, because the formula will draw a line between those two points only.
    • Nah, that is hella wrong. If I do a simple linear between 150°C (0.407v) and 50°C (2.98v) I get the formula Temperature = -38.8651*voltage + 165.8181 It is perfectly correct at 50 and 150, but it is as much as 20° out in the region of 110°C, because the actual data is significantly non-linear there. It is no more than 4° out down at the lowest temperatures, but is is seriously shit almost everywhere. I cannot believe that the instruction is to do a 2 point linear fit. I would say the method I used previously would have to be better.
×
×
  • Create New...