Jump to content
SAU Community

Recommended Posts

Joe nah cant make the JAWS lunch sorry :)

I swear i just saw Denver :confused: either that or they have cloned Denver!!

:) @ the guy in the XR6 checking me out ...... i wouldve loved for someone to put the brakes on in front of him! Wasnt bad looking for a Trev tho.

  • Replies 103.8k
  • Created
  • Last Reply

Top Posters In This Topic

  • GTS-t VSPEC

    20904

  • Nizmo

    13582

  • SHUTO-BOY

    6636

  • skyzerr33

    5353

EWWWW ugly obese ginger haired girl jus twalked past my window ...... tight fitting clothes not being able to contain her fat rolls ..... yuk i think i just reate my sushi roll :spew:

Joe ..... my cat survived being run over by the office chair last night .... stoopid thing Yowlled .... ran out the office ..... came back to the office door and just stood there with her pissed off look at me. So i called her and she came to me (shes quite well trained my cat) and i started patting her and checking if she was hurt in anyway and she was quite smoochy but looked fine ..... must of been because 10 mins later the stupid animal is back to laying right behind the office chair. She doesnt leave my side LOL!

Guest
This topic is now closed to further replies.



  • Latest Posts

    • Yeah, that's fine**. But the numbers you came up with are just wrong. Try it for yourself. Put in any voltage from the possible range and see what result you get. You get nonsense. ** When I say "fine", I mean, it's still shit. The very simple linear formula (slope & intercept) is shit for a sensor with a non-linear response. This is the curve, from your data above. Look at the CURVE! It's only really linear between about 30 and 90 °C. And if you used only that range to define a curve, it would be great. But you would go more and more wrong as you went to higher temps. And that is why the slope & intercept found when you use 50 and 150 as the end points is so bad halfway between those points. The real curve is a long way below the linear curve which just zips straight between the end points, like this one. You could probably use the same slope and a lower intercept, to move that straight line down, and spread the error out. But you would 5-10°C off in a lot of places. You'd need to say what temperature range you really wanted to be most right - say, 100 to 130, and plop the line closest to teh real curve in that region, which would make it quite wrong down at the lower temperatures. Let me just say that HPTuners are not being realistic in only allowing for a simple linear curve. 
    • I feel I should re-iterate. The above picture is the only option available in the software and the blurb from HP Tuners I quoted earlier is the only way to add data to it and that's the description they offer as to how to figure it out. The only fields available is the blank box after (Input/ ) and the box right before = Output. Those are the only numbers that can be entered.
    • No, your formula is arse backwards. Mine is totally different to yours, and is the one I said was bang on at 50 and 150. I'll put your data into Excel (actually it already is, chart it and fit a linear fit to it, aiming to make it evenly wrong across the whole span. But not now. Other things to do first.
    • God damnit. The only option I actually have in the software is the one that is screenshotted. I am glad that I at least got it right... for those two points. Would it actually change anything if I chose/used 80C and 120C as the two points instead? My brain wants to imagine the formula put into HPtuners would be the same equation, otherwise none of this makes sense to me, unless: 1) The formula you put into VCM Scanner/HPTuners is always linear 2) The two points/input pairs are only arbitrary to choose (as the documentation implies) IF the actual scaling of the sensor is linear. then 3) If the scaling is not linear, the two points you choose matter a great deal, because the formula will draw a line between those two points only.
    • Nah, that is hella wrong. If I do a simple linear between 150°C (0.407v) and 50°C (2.98v) I get the formula Temperature = -38.8651*voltage + 165.8181 It is perfectly correct at 50 and 150, but it is as much as 20° out in the region of 110°C, because the actual data is significantly non-linear there. It is no more than 4° out down at the lowest temperatures, but is is seriously shit almost everywhere. I cannot believe that the instruction is to do a 2 point linear fit. I would say the method I used previously would have to be better.
×
×
  • Create New...