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If your looking for some work. There might be a job going on night shift at my work. Pretty easy job. Making irrigation piping and stuff like that. It's down at Ottoway. 38 hours a week and on night shift you get 30% extra on your pay. My father inlaw and Weazy's dad is shift manager.

No worries champ thanks i'll keep that in mind....plastics or metal??

Kinda in limbo atm not sure exactly WHEN im going to be outta a job so its all up in the air atm!

finally got my wheels fitted today. got away with just a mild roll on the rear guards. looks tough as f**k. now running 225/45 ku36 on the front and 215/45 ku25 on the rear.

will be taking it down to morpowa on wednesday to get a power run and make sure the afr's are all good.

umm....working....and picking up tyres for skids.....got 11 13 inch tyres most of them with 80% tread for free

sounds more intersting than my day thats for sure :( sucks heaps at the moment cause im not working :P

I got back to the office after being in Melbourne for work all week.

I actually got to Melbourne on Saturday and did some fun stuff as well. Went to the Salvador Dali exhibit, was amazing, amazing guy.

So today i am doing lots of work, just about to have a conference call.

i wanna go coilovers in mine, gotta convert to S13 stuff tho :P

might just bite the bullet and get some R32 GTS-T hubs, slotted rotors, 32 gts-t calipers, and adapt a knuckle and control arm.

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    • Yeah, that's fine**. But the numbers you came up with are just wrong. Try it for yourself. Put in any voltage from the possible range and see what result you get. You get nonsense. ** When I say "fine", I mean, it's still shit. The very simple linear formula (slope & intercept) is shit for a sensor with a non-linear response. This is the curve, from your data above. Look at the CURVE! It's only really linear between about 30 and 90 °C. And if you used only that range to define a curve, it would be great. But you would go more and more wrong as you went to higher temps. And that is why the slope & intercept found when you use 50 and 150 as the end points is so bad halfway between those points. The real curve is a long way below the linear curve which just zips straight between the end points, like this one. You could probably use the same slope and a lower intercept, to move that straight line down, and spread the error out. But you would 5-10°C off in a lot of places. You'd need to say what temperature range you really wanted to be most right - say, 100 to 130, and plop the line closest to teh real curve in that region, which would make it quite wrong down at the lower temperatures. Let me just say that HPTuners are not being realistic in only allowing for a simple linear curve. 
    • I feel I should re-iterate. The above picture is the only option available in the software and the blurb from HP Tuners I quoted earlier is the only way to add data to it and that's the description they offer as to how to figure it out. The only fields available is the blank box after (Input/ ) and the box right before = Output. Those are the only numbers that can be entered.
    • No, your formula is arse backwards. Mine is totally different to yours, and is the one I said was bang on at 50 and 150. I'll put your data into Excel (actually it already is, chart it and fit a linear fit to it, aiming to make it evenly wrong across the whole span. But not now. Other things to do first.
    • God damnit. The only option I actually have in the software is the one that is screenshotted. I am glad that I at least got it right... for those two points. Would it actually change anything if I chose/used 80C and 120C as the two points instead? My brain wants to imagine the formula put into HPtuners would be the same equation, otherwise none of this makes sense to me, unless: 1) The formula you put into VCM Scanner/HPTuners is always linear 2) The two points/input pairs are only arbitrary to choose (as the documentation implies) IF the actual scaling of the sensor is linear. then 3) If the scaling is not linear, the two points you choose matter a great deal, because the formula will draw a line between those two points only.
    • Nah, that is hella wrong. If I do a simple linear between 150°C (0.407v) and 50°C (2.98v) I get the formula Temperature = -38.8651*voltage + 165.8181 It is perfectly correct at 50 and 150, but it is as much as 20° out in the region of 110°C, because the actual data is significantly non-linear there. It is no more than 4° out down at the lowest temperatures, but is is seriously shit almost everywhere. I cannot believe that the instruction is to do a 2 point linear fit. I would say the method I used previously would have to be better.
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