Jump to content
SAU Community

Recommended Posts

  • Replies 215
  • Created
  • Last Reply

Top Posters In This Topic

should i take it personally that there are no pics of my car or is it a Chevy thing? :P

It is amazing what a ride in a Mazda can do to you - just look at the attached pictures of Chris (evil_weevil). :laugh:

The first shot is leaving the pits and Chris is looking very relaxed.

The next shot has Clinton looking for his breaking point at the side of the track and Chris has a concerned look on his face - you going to think about breaking soon or what????

post-24210-1245673634_thumb.jpg

post-24210-1245673710_thumb.jpg

should i take it personally that there are no pics of my car or is it a Chevy thing? :laugh:
I was think the same thing (except for the whole Chevy thing) but then remembered Matt was in our group :-)

still though a couple of snaps with the arm out the window would've done.

Yep, Bobbeh got it, I would have taken photos of your car if it where in a different session to me :P

Besides, I wouldn't take the camera in the car around the track, it doesn't do video and it weighs heaps! :P

IMO, my favourite photo taken on the day Linky McLink Link

Yep, Bobbeh got it, I would have taken photos of your car if it where in a different session to me :P

Besides, I wouldn't take the camera in the car around the track, it doesn't do video and it weighs heaps! :)

IMO, my favourite photo taken on the day Linky McLink Link

haha, now we're talking Matt!

what a sexy beast, not quite as good looking as the owner but sexy nontheless :)

Actually mate thats probably the best pic i have of my car. Thanks!

Awesome photos cassbo champ!!! I have to say your photography is bloody excellent BUT has me scratching my head as to what the feck my wing is doing under heavy downforce load!!! It looks to be warping on the passanger side, or generating a higher downforce on that side..???!?!?!?! NFI!!

DPP_0196.jpg

Ando - I would say that the passenger's side of the wing is working correctly and that the camers is desturbing the flow of air on the driver's so it is not generating near as much down force.

Charles,

hahahaha that is funny stuff!!!!

As much fun as it is going out showing people bad habbits, I still get a bit nervous when Im not in the drivers seat! brake.....braking yet?? :P

Must say though Clinton did great out there! If he tweaked the suspension a bit, you'll be surprised much better it'll go!

Ando - the boot looks like it has alot of pressure on it (looking at the lines on boot to rear panels)

Thanks guys :)

To tell the truth I got a couple of people I know who have been into photography longer than me (2 months lol) to pick apart my photos and tell me how they can be better. Lets just say with some changes in the settings and some experience we should hopefully see a bit of an increase in quality :P

Just out of curiosity guys, i want to know - some of those cars seemed super quick down the straight... what speeds were being clocked?

I think in the beginner class I clocked out at around 190km/h a few times according to speedo... I reckon the others in group 1 and 2 were going hell quicker though!

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now



  • Similar Content

  • Latest Posts

    • Yeah, that's fine**. But the numbers you came up with are just wrong. Try it for yourself. Put in any voltage from the possible range and see what result you get. You get nonsense. ** When I say "fine", I mean, it's still shit. The very simple linear formula (slope & intercept) is shit for a sensor with a non-linear response. This is the curve, from your data above. Look at the CURVE! It's only really linear between about 30 and 90 °C. And if you used only that range to define a curve, it would be great. But you would go more and more wrong as you went to higher temps. And that is why the slope & intercept found when you use 50 and 150 as the end points is so bad halfway between those points. The real curve is a long way below the linear curve which just zips straight between the end points, like this one. You could probably use the same slope and a lower intercept, to move that straight line down, and spread the error out. But you would 5-10°C off in a lot of places. You'd need to say what temperature range you really wanted to be most right - say, 100 to 130, and plop the line closest to teh real curve in that region, which would make it quite wrong down at the lower temperatures. Let me just say that HPTuners are not being realistic in only allowing for a simple linear curve. 
    • I feel I should re-iterate. The above picture is the only option available in the software and the blurb from HP Tuners I quoted earlier is the only way to add data to it and that's the description they offer as to how to figure it out. The only fields available is the blank box after (Input/ ) and the box right before = Output. Those are the only numbers that can be entered.
    • No, your formula is arse backwards. Mine is totally different to yours, and is the one I said was bang on at 50 and 150. I'll put your data into Excel (actually it already is, chart it and fit a linear fit to it, aiming to make it evenly wrong across the whole span. But not now. Other things to do first.
    • God damnit. The only option I actually have in the software is the one that is screenshotted. I am glad that I at least got it right... for those two points. Would it actually change anything if I chose/used 80C and 120C as the two points instead? My brain wants to imagine the formula put into HPtuners would be the same equation, otherwise none of this makes sense to me, unless: 1) The formula you put into VCM Scanner/HPTuners is always linear 2) The two points/input pairs are only arbitrary to choose (as the documentation implies) IF the actual scaling of the sensor is linear. then 3) If the scaling is not linear, the two points you choose matter a great deal, because the formula will draw a line between those two points only.
    • Nah, that is hella wrong. If I do a simple linear between 150°C (0.407v) and 50°C (2.98v) I get the formula Temperature = -38.8651*voltage + 165.8181 It is perfectly correct at 50 and 150, but it is as much as 20° out in the region of 110°C, because the actual data is significantly non-linear there. It is no more than 4° out down at the lowest temperatures, but is is seriously shit almost everywhere. I cannot believe that the instruction is to do a 2 point linear fit. I would say the method I used previously would have to be better.
×
×
  • Create New...