Jump to content
SAU Community

Recommended Posts

Looks like a fellow member of darker complexion might have been offended of my love for whiter girls :whistling:

im not offended. just how much whiter would you go than the above pic of Kim?

seriously would be some vampire banger if it was whiter than her.

I've never been a big fan of black girls, at least not the ones with stereotypically black features but Kim is nowhere near too dark for me. Yum.

win

Fat ass is just fat ass

full.jpg

kim_kardashian_bikini_booty_2.jpg

If that's as bad as she gets, and these paparazzi style shots at the beach usually show celebrities looking pretty terrible without their makeup and lighting, I'd be very content with that. I prefer small asses too, but as Alex said, that isn't fat...just large hips and a proportionately large ass to suit. Looks toned enough and the rest of her more than makes up for any fault with the ass :)

Ain't too many guys who would be laughing at you with that hanging off your arm!

Cameras give a false perspective of a persons height but now knowing Kim is at least 9" shorter than me, makes things clearer.

When i look at a women, i always look at how i could mount her. If Kim was at my height and with an ass almost double that of mine then that's definitely a no go zone.

I got a mate who just said no to her based on her ass, but he has yellow fever (read: yellow AIDS, he ain't ever coming back), so his idea of a fat ass is anything you can't hold in one hand.

Guest
This topic is now closed to further replies.



  • Similar Content

  • Latest Posts

    • Yeah, that's fine**. But the numbers you came up with are just wrong. Try it for yourself. Put in any voltage from the possible range and see what result you get. You get nonsense. ** When I say "fine", I mean, it's still shit. The very simple linear formula (slope & intercept) is shit for a sensor with a non-linear response. This is the curve, from your data above. Look at the CURVE! It's only really linear between about 30 and 90 °C. And if you used only that range to define a curve, it would be great. But you would go more and more wrong as you went to higher temps. And that is why the slope & intercept found when you use 50 and 150 as the end points is so bad halfway between those points. The real curve is a long way below the linear curve which just zips straight between the end points, like this one. You could probably use the same slope and a lower intercept, to move that straight line down, and spread the error out. But you would 5-10°C off in a lot of places. You'd need to say what temperature range you really wanted to be most right - say, 100 to 130, and plop the line closest to teh real curve in that region, which would make it quite wrong down at the lower temperatures. Let me just say that HPTuners are not being realistic in only allowing for a simple linear curve. 
    • I feel I should re-iterate. The above picture is the only option available in the software and the blurb from HP Tuners I quoted earlier is the only way to add data to it and that's the description they offer as to how to figure it out. The only fields available is the blank box after (Input/ ) and the box right before = Output. Those are the only numbers that can be entered.
    • No, your formula is arse backwards. Mine is totally different to yours, and is the one I said was bang on at 50 and 150. I'll put your data into Excel (actually it already is, chart it and fit a linear fit to it, aiming to make it evenly wrong across the whole span. But not now. Other things to do first.
    • God damnit. The only option I actually have in the software is the one that is screenshotted. I am glad that I at least got it right... for those two points. Would it actually change anything if I chose/used 80C and 120C as the two points instead? My brain wants to imagine the formula put into HPtuners would be the same equation, otherwise none of this makes sense to me, unless: 1) The formula you put into VCM Scanner/HPTuners is always linear 2) The two points/input pairs are only arbitrary to choose (as the documentation implies) IF the actual scaling of the sensor is linear. then 3) If the scaling is not linear, the two points you choose matter a great deal, because the formula will draw a line between those two points only.
    • Nah, that is hella wrong. If I do a simple linear between 150°C (0.407v) and 50°C (2.98v) I get the formula Temperature = -38.8651*voltage + 165.8181 It is perfectly correct at 50 and 150, but it is as much as 20° out in the region of 110°C, because the actual data is significantly non-linear there. It is no more than 4° out down at the lowest temperatures, but is is seriously shit almost everywhere. I cannot believe that the instruction is to do a 2 point linear fit. I would say the method I used previously would have to be better.
×
×
  • Create New...